How far is it from Calmar, AB to Springbrook, AB?

The distance between Calmar, AB and Springbrook, AB is 141 km by road.

How long does it take to drive from Calmar, AB to Springbrook, AB?

The drive from Calmar, AB to Springbrook, AB takes approximately 1 h 50 min by car.

The fastest route from Calmar, AB to Springbrook, AB covers 141 km with a driving time of approximately 1 h 50 min.

Springbrook, AB lies roughly to the south of Calmar, AB.

The drive from Calmar, AB to Springbrook, AB mainly follows 795, 2. The longest single stretch is 87 km on 2.

Towns on the route from Calmar, AB to Springbrook, AB include Ponoka, Lacombe, Red Deer, Penhold.

Distance: 141 kmDrive time: 1 h 50 min

Driving from Calmar, AB to Springbrook, AB takes about 1 h 50 min via 2. The distance is 141 km. The straight-line distance is 120 km. Driving directions

Driving directions12 · 141 km

The return trip from Springbrook, AB to Calmar, AB covers roughly the same distance, 141 km.

No notable attractions were found along this route.

Distance and drive time are computed from OpenStreetMap road data with the OSRM routing engine. Updated 4 September 2026.

How far is it from Calmar, AB to Springbrook, AB?: The distance between Calmar, AB and Springbrook, AB is 141 km by road.
How long does it take to drive from Calmar, AB to Springbrook, AB?: The drive from Calmar, AB to Springbrook, AB takes approximately 1 h 50 min by car.
What is the best route from Calmar, AB to Springbrook, AB?: The fastest route from Calmar, AB to Springbrook, AB covers 141 km with a driving time of approximately 1 h 50 min.
Which direction is Springbrook, AB from Calmar, AB?: Springbrook, AB lies roughly to the south of Calmar, AB.
Which roads does the route from Calmar, AB to Springbrook, AB follow?: The drive from Calmar, AB to Springbrook, AB mainly follows 795, 2. The longest single stretch is 87 km on 2.
Which towns do you pass between Calmar, AB and Springbrook, AB?: Towns on the route from Calmar, AB to Springbrook, AB include Ponoka, Lacombe, Red Deer, Penhold.